Tentukan invers dari f (x)= akar x^2 + 1 dan g (x) = 1/x-2

f(x)= √(x² +1)
y = √(x² + 1)
y² = x² + 1
x² = 1 - y²
x = √(1  - y²)

f⁻¹ (x)= √(1 - x²)


g(x) =  1/(x -2)
y =  1/( x- 2)
y(x - 2)  = 1
xy - 2y = 1
xy = 1 + 2y
x = (1 + 2y)/y = (2y +1)/(y)

g⁻¹(x)= (2x + 1) /(x)