jika ⁴log 64²k+¹=9 maka nilai x k adalah

⁴log 64^(2k + 1) = 9
64^(2k + 1) = 4^9
4^3(2k + 1) = 9
3(2k + 1) = 9
2k + 1 = 3
k = 1 ✔

jika ᵃlog b = n
maka  b= aⁿ

⁴log (64)^(2k+1)  = 9

(64)^(2k +1) = 4⁹
(4³)^(2k +1) = (4)⁹

3(2x + 1) = 9
2x + 1 = 9/3 
2x + 1 = 3
2x = 2
x = 1