Jawaban dari g(x)=x+3 dan (fog) (x)=x²+3x-4 adalah

[tex]g(x)=x+3 \\ (fog) (x)= {x}^{2} +3x-4 \\ f(g(x)) = {x}^{2} +3x-4 \\ f(x + 3) = {x}^{2} +3x-4 \\ f(x + 3) = {(x + 3)}^{2} - 3x - 13 \\ f(x + 3) ={(x + 3)}^{2} - 3(x + 3) - 4 \\ f(x) = {x}^{2} - 3x - 4[/tex]

g(x) = x + 3
a = x + 3
x = a - 3

f(g(x)) = x² + 3x - 4
f(a) = (a - 3)² + 3(a - 3) - 4
f(a) = a² - 6a + 3a + 9 - 9 - 4
f(a) = a² - 3a - 4
f(x) = x² - 3x - 4