diketahui h(x) = x + 5, jika (h•g)(x) = 8x - 5/ x - 1; x≠1, rumus fungsi g adalah?

h(x) = x + 5

h(g(x)) = (8x - 5)/(x - 1)
g(x) + 5 = (8x - 5)/(x - 1)
g(x) = (8x - 5)/(x - 1) - 5
g(x) = ((8x - 5) - 5(x - 1))/(x - 1)
g(x) = 3x / (x - 1) ✔

h(x) = x + 5 , (h ο g)(x) = 8x - 5/x - 1 , g (x) = ...?
h(g(x)) = 8x - 5/x - 1
dimisalkan g (x) sebagai y , maka
h(y) = 8x - 5/x - 1
y + 5 = 8x - 5/x - 1
y = (8x - 5/x - 1) - 5
y = 3x/ x - 1

sehingga, nilai g(x) = 3x / x-1
semoga bermanfaat ...