perbandingan tinggi dan diameter tabung 1:1. Jika jari-jari tabung 1 cm maka volume bejana tabung

volume bejana
[tex]v = \frac{1}{4} {d}^{2} \pi \times t \\ v = \frac{1}{4} \times {1}^{2} \times \frac{22}{7} \times 1 \\ v = \frac{22}{28} \\ v = 0.785 {cm}^{2} [/tex]