Tolong bantuannya ❤.

Karena,

[tex]\tan(60^0)= \frac{AB}{20-12} \quad maka\quad \sqrt{3}= \frac{AB}{8} [/tex]

Jadi [tex]AB=8 \sqrt{3} [/tex]

Selanjutnya

[tex]CD= \sqrt{8^2+(8 \sqrt{3})^2 } \\ CD= \sqrt{64+64(3)} \\ CD= \sqrt{6+192} \\ CD= \sqrt{256} \\ CD=16[/tex]

Luas trapesium adalah:

[tex] (\frac{20+12}{2})\times8 \sqrt{3}= 128 \sqrt{3} [/tex]