penyelesaian dari persamaan log(2x-5)+log(x+3)=1+log3. dimohon bantuannya

Bab Logaritma
Matematika SMA Kelas X

log (2x - 5) + log (x + 3) = 1 + log 3
log ((2x - 5) (x + 3)) = log 10 + log 3
log (2x² + 6x - 5x - 15) = log (10 . 3)
2x² + x - 15 = 30
2x² + x - 15 - 30 = 0
2x² + x - 45 = 0
(2x - 9) (x + 5) = 0
2x - 9 = 0
2x = 9
x = 9/2

x + 5 = 0
x = -5

syarat
2x - 5 > 0
2x > 5
x > 5/2

x + 3 > 0
x > -3

maka, x = 9/2