selesaian dari sistem persamaan 3x+2y-4=0 x-3y-5=5 tolong pliss

3x+2y-4 = 0
x-3y-5 = 5


3x+2y-4 = 0 dikali 3
x-3y - 5 = 5 dikali 2

9x + 6y-12 = 0
2x - 6y-10 = 10
____________+
11x-22 = 10
11x = 10+22
11x = 32
x = 32/11



3x+2y-4 = 0 dikali 1
x-3y - 5 = 5 dikali 3

3x + 2y - 4 = 0
3x - 9y - 15 = 15
______________--
11y +11 = - 15
11y = - 15 - 11
11y = - 26
y = - 26/11




3x +2y=4
x-3y= 10

9x +6y = 12
2x - 6y = 20
____________+
11x = 32
x = 32/11


3x +2y=4
x-3y= 10

3x + 2y = 4
3x - 9y = 30
___________--
11y = - 26
y = - 26/11



x = 32/11
y = - 26/11



Maaf kalau salah... Maaf lama lagi disekolah lagi belajar :v