hasil dari [tex] \sqrt{50} - \sqrt{108} + 2 \sqrt{12} + \sqrt{32} = [/tex]

[tex] \sqrt{50} - \sqrt{108} + 2 \sqrt{12} + \sqrt{32} \\ = \sqrt{25 \times 2} - \sqrt{36 \times 3} + 2 \sqrt{4 \times 3} + \sqrt{16 \times 2} \\ = 5 \sqrt{2} - 6 \sqrt{3} + (2 \times 2) \sqrt{3} + 4 \sqrt{2} \\ = 5 \sqrt{2} + 4 \sqrt{2} - 6 \sqrt{3} + 4 \sqrt{3} \\ = (5 + 4) \sqrt{2} - 6 + 4 \sqrt{3} \\ = 9 \sqrt{2} - 2 \sqrt{3} [/tex]
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