4x+3y=6 dan 2x-y=3 menggunakan metode substitusi x +4y =8 dan 2x-y=3 dengan metode gabungan #tolong jawab secepatnya ya plisss...

2x - y = 3
- y = - 2x + 3
y = 2x - 3
subtitusi
4x + 3y = 6
4x + 3(2x - 3) = 6
4x + 6x - 9 = 6
10x = 6 + 9
10x = 15
x = 15/10
x = 3/2
subtitusi
y = 2x - 3
y = 2(3/2) - 3
y = 3 - 3
y = 0
hp = ( 3/2 , 0 )


x + 4y = 8 |×2
2x - y = 3
maka
2x + 8y = 16
2x - y = 3
------------------(-)
9y = 13
y = 13/9
subtitusi
x + 4y = 8
x + 4(13/9) = 8
x + 52/9 = 8
x = 8 - 52/9
x = 72/9 - 52/9
x = 20/9
hp = ( 20/9 , 13/9)

Semoga membantu, mohon koreksinya :))