Matematika

Pertanyaan

suatu fungsi f(x)=7-2x terdenfisi pasangan berurutan [(a,5) (b,1) (c,-3)(d,-7) nilai a+B-c+d adalah

2 Jawaban

  • jawab

    f(x)=  7 - 2x
    f(a)= 5
    7 - 2a = 5
    2a = 2
    a= 1

    f(b) = 1
    7 - 2b= 1
    2b = 8
    b = 4

    f(c)= - 3
    7 - 2c = -3
    2c =10
    c= 5

    f(d)= - 7
    7 - 2d = -7
    2d = 14
    d= 7

    a+b+c+d = 1 +4 + 5+ 7 
    = 17
  • Persamaan fungsi f(x) = 7 - 2x

    (a,5)............ x = a; f(a) = 5
    f(a) = 7 - 2a
    5 = 7 - 2a
    5 - 7 = -2a
    -2 = -2a
    a = -2 / -2
    a = 1

    (b,1)............ x = b; f(b) = 1
    f(b) = 7 - 2b
    1 = 7 - 2b
    1 - 7 = -2b
    -6 = -2b
    b = -6 / -2
    b = 3

    (c,-3)............ x = c; f(c) = -3
    f(c) = 7 - 2c
    -3 = 7 - 2c
    -3 - 7 = -2c
    -10 = -2c
    c = -10 / -2
    c = 5

    (d,-7)............ x = d; f(d) = -7
    f(d) = 7 - 2d
    -7 = 7 - 2d
    -7 - 7 = -2d
    -14 = -2d
    d = -14 / -2
    d = 7

    Nilai a + b + c + d adalah
    = 1 + 3 + 5 + 7
    = 16

    Jadi nilai a + b + c + d adalah 16.

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