Matematika

Pertanyaan



Bentuklah menjadi persamaan kuadrat

(3a-2b)(2a+6) =

(-2x+4)(x-7) =

(3m-4)(3m+4) =

(-x+7)( -x+8) =

(4p-3q)(4p+3q) =

1 Jawaban

  • (3a-2b)(2a+6)
    = 6a² + 18a - 4ab - 12b

    (-2x+4)(x-7)
    = -2x² + 14x + 4x - 28
    = -2x² + 18x - 28

    (3m-4)(3m+4)
    = 9m² + 12m - 12m - 16
    = 9m² - 16

    (-x+7)( -x+8)
    = x² - 8x - 7x + 56
    = x² - 15x + 56

    (4p-3q)(4p+3q)
    = 16p² + 12pq - 12pq - 9q²
    = 16p² - 9q²

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