Mohon bantuannya ya para sobat sobat

( 4a-²b²c / 12a-^5 b⁴c-¹ ) -¹

= 12a²b⁴
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4a^5b²c¹c¹

= 12a²b⁴
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4a^5b²c²

= 3b²
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a³c²

( C )

[tex]( \frac{4 {a}^{ - 2} {b}^{2} c }{12 {a}^{ - 5} {b}^{4} {c}^{ - 1} } )^{ - 1} = ( \frac{4 {a}^{2} {b}^{ - 2} {c}^{ - 1} }{12 {a}^{5} {b}^{ - 4} c} ) = ( {3 {a}^{ - 3} {b}^{2} {c}^{ - 2} } ) = \frac{{a}^{3}{c}^{2}}{ {3b}^{2} } [/tex]
semoga membantu
jadikan jawaban terbaik