tentukan persamaan garis yg melalui titik (3,2) dan sejajar garis 2y=6x+10

Rumus =
y-y1 = m(x-x1)
m = x/y = 6/2 = 3
y-2 = 3(x-3)
y-2 = 3x-9
3x-y = -9+2
3x-y = -7
3x-y+7 = 0