soal mtk cara cariknya
Matematika
rhm10
Pertanyaan
soal mtk cara cariknya
1 Jawaban
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1. Jawaban hakimium
Eksponen & Logaritma
Matematika X
[1].
[tex] \frac{2^{4}.9^{-2}.5^{-3}}{8.3^{-5}.125^{-1}} [/tex]
[tex] \frac{2^{4}.3^{-4}.5^{-3}}{2^{3}.3^{-5}.5^{-3}} [/tex]
[tex]2^{4-3}.3^{5-4}[/tex]
= 2 x 3
= 6
[2].
Jika yang dimaksud [tex]^{5}log6[/tex]
[tex]= \frac{log6}{log5} [/tex]
[tex]= \frac{log 2 + log 3}{log 10 - log 2} [/tex]
[tex]= \frac{a+b}{1-a} [/tex]
Jika yang dimaksud 5.log 6
= 5.(log 2 + log 3)
= 5.(a + b)
= 5a + 5b
[3].
= 4√3 + 3√12 - √27
= 4√3 + 3√(4 x 3) - √(9 x 3)
= 4√3 + 3 x 2√3 - 3√3
= 4√3 + 6√3 - 3√3
= (4 + 6 - 3)√3
= 7√3