X+y +2z= 6, 3x-y+z =4, 2x-2y = 2 tentukan nilai z, x, y

x + y+ 2z=6 | x1
3x-y+ z =4 | x2
_____________
x + y +2z=6
6x- 2y+2z=8
_____________ _
-5x +3y = -2 |x 2
2x -2y = 2 | x 3
_____________
-10x +6y = -4
6x - 6y = 6
___________ +
-4x = 2
x= - 2/4
x = -1/2

• 2x - 2y = 2
2(-1/2) -2y=2
-1 -2y=2
-2y= 2+1
y= -3/2
• x+y+2z=6
-1/2 -3/2+2z =6
-4/2 +2z. = 6
-2. +2z=6
2z=8
z= 4