persen massa karbon dan glukosa ( C6H12O6) ( Ar C= 12, O= 16, H=1 ) adalah ....

[tex] c_{6}h_{12}o_{6} \\ mr \: glukosa \\ c = 12 \times 6 = 72 \\ h = 12 \times 1 = 12 \\ o = 6 \times 16 = 96 \\ mr = 96 + 12 + 72 = 180 \\ \% \: massa \: karbon = \frac{6 \times 12}{180} \times 100\% = \frac{72}{180} \times 100\% = 40\%[/tex]

Maaf kalo salah, semoga membantu