Sebuah kerucut alasnya berdiameter 180 cm dan garis pelukisnya 150 cm (v :3,14) hitunglah A: tinggi kerucut B:volume kerucut C,luas permukaan kerucut Tolong y

a. tinggi kerucut :

t²=s²-r²
=150² - 90²
=22.500 - 8.100
=14.400
=√14.440
=120 cm

b. V kerucut :

=1/3×Πr²t
=1/3×3,14×90²×120
=1/3×3.052.080
=1.017.360 cm³

c. luas permukaan kerucut
=Πr (r+s)
=3,14×90 (90+150)
=282,6 (240)
=67.824 cm²

A.t^2 = s^2 - r^2
t^2 = 150^2 - (180/2)^2
t^2 = 22500 - 8100
t^2 = 14400
t = 120 cm

b. V = 1/12.phi.d^2.t
= 1/12.3,14.180.180.120
= 1.017.360 cm^3

c.lp = phi.r.(s+r)
= 3,14.90(150+90)
= 67.824 cm^2